Easy Trig Math Problem, Can You Do it?

Question

Here's the problem, I can't figure this out.
http://i34.photobucket.com/albums/d141/darealbigtigga/tough.jpg
.
.
.

Answer 1

the anser is 3837354743569432598475864325435209759 / 0

Answer 2

5x+y = 0, x >= 0

This implies the cosine values must be positive or zero; so the sine values are negative.

5x+y = 0 --> 5x = -y --> 5 = -y/x --> 1/5 = x/-y = 1/-(-5)

This last assertion must be true, because the y values must be negative.

Hypotenuse of triangle is:

sq rt [1^2 + (-5)^2] = sq rt [1 + 25] = sq rt (26)

sin A = y/hyp = -5/sq rt (26) = -5sq rt (26)/ 26
cos A = x/hyp = 1/sq rt (26) = sq rt (26)/26
tan A = y/x = -5/1 = -5

csc A = 1/sin A = sq rt (26)/-5
sec A = 1/cos A = 26/sq rt (26) = sq rt (26)
cot A = 1/tan A = 1/-5

Answer 3

if it's easy then y can't u figure it out?