if rectangular box of 2x20x8 is to be completely wrapped with paper. If a single sheet of paper is to be used without patching, then the dimensions of the paper could be:
(A) 17 in by 25 in
(B) 21 in by 24 in
(C) 24 in by 12 in
(D) 24 in by 14 in
(E) 26 in by 14 in
2006-12-11 16:02:12 · 7 answers · asked by Amuthan A 1 in Science & Mathematics ➔ Mathematics
The area of the paper which can wrap all the sides of the box should be atleast as large as the total surface area of the box, which is 2 * ( 20 * 8 + 20 * 2 + 8 * 2) = 432 sq. in.
Among the options, there seems to be none that big except B. And from the language of the question, as it does not look to be looking for a definite correctly sized answer, it seems to look for an approximate or a realistic answer, B should be right.
2006-12-11 21:56:38 · answer #1 · answered by pravkas 2 · 0⤊ 0⤋
21 in by 24 in
2006-12-11 16:11:07 · answer #2 · answered by ▓▓▓▓^^]AnTisH[^^▓▓▓▓ 2 · 1⤊ 0⤋
International paper sizes
A0 841 X 1189
A1 594 X 841
A2 420 X 594
A3 297 X 420
A4 210 X 297
A5 148 X 210
A6 105 X 148
A7 74 X 105
all the above dimensions are in mm
2006-12-11 16:23:58 · answer #3 · answered by venky 1 · 0⤊ 0⤋
None of them is right. The box is to be fully covered means the paper should cover all four sides plus top plus bottom. That way, the paper dimensions shall be 2(l+h) and 2(b+h) i.e. 44" x 20".
If we assume a top open box or that top need not be covered, then answer will be C i.e. 24" x 12"
2006-12-11 16:12:07 · answer #4 · answered by Srinivas c 2 · 0⤊ 1⤋
The total surface area of the rectangular box that you have to cover is of course 2(2*20+20*8+2*8)=432in. However this matches with none of the options. Are you sure you have taken down the options correctly?
2006-12-11 16:17:26 · answer #5 · answered by Anonymous · 0⤊ 1⤋
paper
2017-02-28 01:53:21 · answer #6 · answered by ? 7 · 0⤊ 0⤋
E
2006-12-11 16:10:53 · answer #7 · answered by Pokkiri 3 · 0⤊ 1⤋