Question for homework that I don't know how to solve it... =/
Say a bromoalkane's molecular formula is given that undergoes E2 reaction and a product forms, how do I know the skeletal structure of the bromoalkane?
Ex.
C6H13Br -- E2 --> 2-ethylbutene
C5H9Br -- E2 --> 3-methylcyclobutene
C8H15Br -- E2 --> 3,3-dimethylcyclohexene
How do I know how to go backward?
2006-12-11 15:41:35 · 2 answers · asked by AUNIDLY 1 in Science & Mathematics ➔ Chemistry
Can someone show me how to do the first two example? the C6H13Br and the C5H9Br? What are their skeletal structure before the E2 Reaction?
2006-12-11 15:52:20 · update #1
Draw out the product, and the reactant will be exactly the same except that where the product has a double bond, the reactant will have a single bond with H on one carbon and Br on the other. The skeletal structure will be the same except for the single bond where the product has a double bond.
2006-12-11 15:44:57 · answer #1 · answered by Amy F 5 · 0⤊ 0⤋
Remove the double bond from the product and the bromine will be attached to the more highly substituted of the two carbons the double bond was between.
2006-12-11 23:45:10 · answer #2 · answered by neverbeenc00l 1 · 0⤊ 0⤋