You want to lift a 150N object up to a back of a trunk that is 1.2m high. The ramp is 5.0 m long and the coefficent of friction is 0.15. Assume it is moving at constant velocity. Find the Force applied.
can you please explain why in this problem you use the sin of theta and not the cosine?
2006-12-11 14:57:52 · 3 answers · asked by socom_lover 2 in Science & Mathematics ➔ Physics
id like to see how it is solved also,
thanks
2006-12-11 15:10:09 · update #1
to find the angle:
sin^-1(1.2/5)= 13.9 degrees
Fw(x)=sin(13.9)150N=36N
Fw(y)=cos(13.9)150N=145.6N
Fnormal is equal to Fw(y). Fnormal=145.6
Friction= mu(Fnormal)
Friction= (.15)(145.6N)=21.84N
since Friction, Fapply and Fw(x) are the Fnet and both Friction and Fw(x) are same direction, we add them up
Fw(x)+Friction= 21.84N+36N=57.84N
Because you are pushing the object at a constant speed, all the forces are balanced. So Fapply is also 57.84N
2006-12-11 15:16:39 · answer #1 · answered by 7 · 0⤊ 0⤋
Is this an exam question?
2006-12-11 15:08:48 · answer #2 · answered by schnauzer 4 · 0⤊ 0⤋
you want to find distance travelled (hypotneuse)?
That would be my guess.
2006-12-11 15:10:24 · answer #3 · answered by Kipper to the CUP! 6 · 0⤊ 0⤋