i want an answer as to how to factor that problem.
2006-12-11 14:53:12 · 9 answers · asked by Caitlin Z 1 in Science & Mathematics ➔ Mathematics
4x(2x^2+17x-30)
2x^2+17x-30
x=[-17+/-rt(289+240)]/4
x=[-17+/-23]/2
=-20 or 3
so the factors are 4x,(x+20) and (x-3)
4x(x+20)(x-3)
2006-12-11 15:00:34 · answer #1 · answered by raj 7 · 1⤊ 1⤋
first, factor out 4 from each term: 2x^2+17x - 30. terms must have opposite signs inside parentheses because 30 is negative. factors must algebraically add to +17. factors of 30 are 2/15,3/10,5/6. pairs these with 2/1, the factors of 2(in x^2 term): (2x^2 -3)(x^2 + 10)
2006-12-11 23:04:24 · answer #2 · answered by R. Paul I 1 · 2⤊ 0⤋
8x³ + 68x² - 120x
4x (2x² + 17 - 30x)
4x (x + 10)(2x - 3)
2006-12-11 23:00:27 · answer #3 · answered by M. Abuhelwa 5 · 2⤊ 0⤋
Pull out the 4x value:
4x(2x^2+17x-30)
4x(2x-3)(x+10)
4x=0,2x-3=0
x+10=0
x=0,3/2, and -10
2006-12-11 23:30:09 · answer #4 · answered by Anonymous · 1⤊ 0⤋
4x(2x² + 17x - 30x) = 4x (x + 10)(2x - 3) = 0
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2006-12-11 23:13:29 · answer #5 · answered by aeiou 7 · 2⤊ 0⤋
8x^3+68x^2-120x
4x(2x^2+17x-30x)
4x(2x-3)(x+10)
x=0
x=1.5
x=10
2006-12-11 22:55:01 · answer #6 · answered by mr_mumbles_nyc 3 · 2⤊ 1⤋
find the gcf of 8, 68, 120. then circle whats common in all three of them. then you get the gcf. then divide each of those terms by the gcf you got. put the final answer in parentheses times your gcf.
2006-12-11 22:55:45 · answer #7 · answered by HOEMYJIZM. 2 · 0⤊ 3⤋
4x(x+10)(2x-3)
2006-12-11 22:58:39 · answer #8 · answered by 7 · 2⤊ 0⤋
Og! why must you ask such a question?????
2006-12-11 22:56:19 · answer #9 · answered by tcbtoday123 5 · 0⤊ 2⤋