4^x=16 * sqrt(2)
Thanks to everyone on the last one. We got through about five more problems after that.
2006-12-11 14:26:33 · 4 answers · asked by cezzium 4 in Science & Mathematics ➔ Mathematics
I'm not getting where the .5 comes from
2006-12-11 14:36:59 · update #1
DO YOUR OWN HOMEWORK!
2006-12-11 14:31:19 · answer #1 · answered by Megan D 2 · 0⤊ 2⤋
4^x = 16â2
by taking log for the both side
log 4^x = log16*â2
x log4 = log16 + 1/2 log2
x = ( log16 + 1/2log2) / log4
x = 2.25
2006-12-11 22:36:31 · answer #2 · answered by M. Abuhelwa 5 · 0⤊ 0⤋
4^x=16 * sqrt(2) take ln's of both sides
x ln 4=ln 16+.5 ln 2
2x ln 2=4 ln 2 +.5 ln 2 divide by ln 2
2x=4.5
x=2.25
2006-12-11 22:30:13 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
4^x = 16 * sqrt(2)
log 4^x = log (16 * sqrt(2)) .......... (at base 4)
x*log 4 = log 16 + log 2^1/2
x = log 4² + log (4^1/2)^1/2
x = 2*log 4 + log 4^1/4
x = 2 + (1/4)log 4
x = 2 + 1/4
x = 2.25
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2006-12-11 22:35:02 · answer #4 · answered by Ana paula 3 · 0⤊ 0⤋