My son is not having a good night and i'm using points!
2^x=100
2006-12-11 14:01:46 · 4 answers · asked by cezzium 4 in Science & Mathematics ➔ Mathematics
How would this work if the unknown exponent were negative?
e^-x=.01
2006-12-11 14:17:15 · update #1
Taking logs of both sides, xlog(2) = log(100), x=6.64386
2006-12-11 14:03:50 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Take the log of it > Log to base 2 of 100=x
Using the change of base property we get (all logs will be in base 10 from now on) Log100/log2
Simplify log100/log2 on a calculator (should be in base 10), and you're done
2006-12-11 14:05:23 · answer #2 · answered by plasticglasses24 4 · 0⤊ 0⤋
2^x=100 take the log of both sides
x ln 2=ln 100 divide by ln 2
x=ln 100 / ln 2=6.644
If you have a negative exponent, you do it the same way.
2006-12-11 14:28:13 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
2^x=100. Take logarithms on both sides.
log (2^x)=log 100
x*log 2=log 100
Hence x=log 100/log 2.
Substitute the values of log 100 and log 2 (from a logarithm table) and you get the answer.
2006-12-11 14:06:16 · answer #4 · answered by greenhorn 7 · 0⤊ 0⤋