I am into gravity. I want to know how the opposite force of gravity manifests itself.
2006-12-11 13:40:47 · 7 answers · asked by edfinite2005 2 in Science & Mathematics ➔ Physics
At the center of the Earth's mass, you would weigh nothing. Parts of you would have weight being pulled outward toward the nearer mass. That weight would be so small you could neglect it. It would be impossible to measure.
2006-12-11 13:57:55 · answer #1 · answered by Jack 7 · 1⤊ 0⤋
A little less because the gravitational pull at the centre of Earth is less as compared to the gravitational pull at the poles.Since weight is the product of mass and gravitational pull you would weigh less at the equator(centre of Earth).
2006-12-11 13:50:40 · answer #2 · answered by manu 2 · 0⤊ 0⤋
you would weigh nothing. The center of earth would have mass pulling on you in all directions. This would cancel each other out making your weight zero
2006-12-11 13:43:39 · answer #3 · answered by Anonymous · 1⤊ 0⤋
yeah... it's not as simple as they make it sound.
To weigh nothing, you'd have to be a dot and have no thermal energy whatsoever.
If you're bigger of if you have any kind of energy, there is no stable levitation. You can refer to Ernshaw's theorem for that. The classical application is with electrostatic forces, but it can be applied to graviy as well. So, eventually, you'd be attracted to a side of your cavity and thus have a weight
2006-12-11 14:17:11 · answer #4 · answered by Vincent L 3 · 1⤊ 0⤋
I agree with mckay a. You would weigh 0.
2006-12-11 13:57:57 · answer #5 · answered by sojsail 7 · 1⤊ 0⤋
theoretically you would weigh nothing since there is equall force pulling you in all directions
2006-12-11 14:00:12 · answer #6 · answered by traxx10 2 · 1⤊ 0⤋
man, just screw it.
you'll have MOREEEE than enough to think about "gravity" if/when you ever take a physics course.
Dont waste time screwing ur self over now, ull have to do it then anyway
just relax, and look up at the stars!
2006-12-11 13:43:30 · answer #7 · answered by Anonymous · 0⤊ 2⤋