f 10 moles of NH3 were produced, how many moles of N2 would be required?

Question

please explain the answer ?

If* is the first word. please explain the answer

no the question is IF 10 moles of NH3 were produced, how many moles of N2 would be required?
Equation is N2 + 3H2 ----> 2 NH3

Answer 1

If by some miracle I did the math right, it's 65.38 mol. If not, then I'm sorry. I tried =]

Answer 2

Is this the reaction.... ?

N(2) + 3H(2) ----> 2 NH(3)

If so, you just multiply through by 5.
Always find the basic reaction, then multiply everything through until you have the number of moles of product that you want.

so....

5 N(2) + 15 H(2) ---> 10 NH(3)

Always make sure that you have the same number of each type of atom on the reactant and product sides.

Reactant:
5 moles * 2 N atoms per mole = 10 N atoms
15 moles * 2 H atoms per mole = 30 H atoms

Product:
10 moles * 1 N atom per mole = 10 N atoms.
10 moles * 3 H atoms per mole = 30 H atoms

If you don't understand balancing equations and stoichiometry, see your teacher or a tutor.

Answer 3

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Answer 4

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Answer 5

do you mean NF 1 and NF 2 ?

Answer 6

its 5N2. the equation
5N2+ 15H2----10NH3

Answer 7

what are talkin about???