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What is the effect of the force of gravity on an object thrown upward?

2006-12-11 13:14:26 · 9 answers · asked by Fatima 1 in Science & Mathematics Physics

9 answers

it causes the object to decelerate, stop, and then accelerate in towards the center of the earth. The rate of acceleration is 9.8 meters / second squared

2006-12-11 13:17:14 · answer #1 · answered by Jack B. Nimble 2 · 0 0

Gravity is a phenomenon through which all objects attract each other. The earth is a giant object object and will exert it's effect on anything thrown upward. The gravitational field of an object is numerically equal to the acceleration of objects under its influence, and its value at the Earth's surface, (called g), is approximately 32 ft/s². This means that, ignoring air resistance which causes friction, an object falling freely near the earth's surface increases in speed by 9.807 m/s (around 32 mph) for each second of its fall. Now, the really crazy part; the Earth itself experiences an equal and opposite force to that acting on the falling object, meaning that the Earth also accelerates towards the object. However, because the mass of the Earth is so large, the measurable acceleration of the Earth by this same force is negligible. So, old Isaac was correct - what goes up, will come down.

2006-12-11 13:26:36 · answer #2 · answered by rnrayunretired 3 · 0 0

The force of gravity on an object thrown upward... Gravity, pulls on the object opposing the momentum it gained from being thrown slowing it down, then eventually pulling it back down toward earth. Ya it makes things that go up come back down.

2006-12-11 13:23:47 · answer #3 · answered by Anonymous · 0 0

As the object is travelling upward, the force due to gravity is:
F=m*g (where g= -9.81 m/s/s and m=mass of the object)
I.e. gravity is slowing the object down gradually.

The object will travel upwards until it reaches its maximum height, where its velocity becomes 0. At this point, the force of gravity acts to pull the object back towards the earth. Therefore:
F=m*g (where g= +9.81m/s/s)

Essentially, when travelling upwards, gravity acts to DECELERATE the object at a rate of 9.81m/s/s, and when it is travelling downwards again, gravity acts to ACCELERATE the object, at the same rate of 9.81m/s/s.

2006-12-11 13:29:37 · answer #4 · answered by Michael Murphy 2 · 0 0

Ignoring friction, an object will come back at the same speed it left with. Gravity will act on the objest for X seconds until it stops. Then it will act on the object for X seconds as it falls back to Earth.

2006-12-11 13:20:20 · answer #5 · answered by Anonymous · 0 0

No. Centrifugal rigidity and gravity are thoroughly distinctive. Centrifugal rigidity is a rigidity created by using pass. This rigidity basically happens while some thing is spinning. If the spinning stopped, the rigidity might end besides. Gravity is a rigidity via mass. whether the Earth stopped spinning, we'd nonetheless experience the same gravity because of the fact the mass of the Earth remains the same.

2016-10-18 03:35:56 · answer #6 · answered by felio 4 · 0 0

when a body is thrown up, gravity acts against its motion and acts as negative acceleration. therefore the body will slow down, reach its maximum height depending on the initial velocity and fall back to the ground accelerating, as, now, when it is falling back, gravity is positive. g=9.8m/s^2.

2006-12-11 13:20:59 · answer #7 · answered by SRM 1 · 0 0

Simple.
It begins to pull the object downward, once it begins to come to a stop (when its inertial energy is depleted) and it falls to the earth!

2006-12-11 13:19:06 · answer #8 · answered by Ammy 6 · 0 0

It pulls it downwards ......Newton's first law if you replace accelration with 'g' gravitations force of accelration of earth

2006-12-11 13:17:35 · answer #9 · answered by Inquistive_man 3 · 0 0

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