25x^2 - 30x + 9 = 0 how do i do that by factoring
2006-12-11 13:09:55 · 6 answers · asked by Tony Fiorilli 1 in Science & Mathematics ➔ Mathematics
(5x-3)^2
2006-12-11 13:11:41 · answer #1 · answered by d.treadway 2 · 0⤊ 0⤋
25x² - 30x + 9 = 0
5²x² - 2*3*5x + 9 = 0
(5x)² - 2*3*5x + 3² = 0
a² - 2ab + b² = (a-b)²
=>
25x² - 30x + 9 = (5x - 3)²
x = 3/5
₢
2006-12-11 21:14:59 · answer #2 · answered by Luiz S 7 · 0⤊ 0⤋
25x^2 - 30x + 9 = 0
(5x-3)^2=0
5x-3=0
x=3/5
2006-12-11 21:24:49 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
25x^2-30+9=0
(5x-3)(5x-3)=0
5x-3=0 and 5x-3=0
+3 +3
5x=3 5x=3
x=3/5 x=3/5
2006-12-11 21:14:40 · answer #4 · answered by Mandy 2 · 0⤊ 0⤋
You have to just kinda look at it and do a lot of factoring; try this first:
(5x-3)(5x-3) = 0
I got it the first time, by looking at the first and last terms ie how to get 25 then +9 and do the cross terms add up to the middle coefficient of x.
2006-12-11 21:12:56 · answer #5 · answered by kellenraid 6 · 0⤊ 0⤋
dont know
2006-12-11 21:12:11 · answer #6 · answered by little princess 2 · 0⤊ 0⤋