HI!!! I need somebody's help!!! My final for my chemistry semester is tomorrow!!!!!!!!!!!! PLEASE HELP!!!!!!!!!
2006-12-11 12:59:07 · 4 answers · asked by D!@Nn@ 2 in Science & Mathematics ➔ Chemistry
The oxidation number of Hydrogen in a compound like LiH, which is named Lithium Hydride is minus 1 (-1).
When you see HYDRIDE, it is -1. When you see Hydronium, proton, the it is +1.
2006-12-11 13:04:55 · answer #1 · answered by Aldo 5 · 0⤊ 0⤋
The oxidation number of H in metal compounds like sodium hydride, NaH, is -1. This is in contrast to the +1 oxidation number of H in all other types of compounds, like water, H2O. Similarly in sodium borohydride, NaBH4. Na=+1, B=+3 H= -1
2006-12-11 13:04:40 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋
the molecular formula of tertrathionate is s4o6^-2 the entire fee on the atom is -2 so each and each and every of the element s oxidation style might want to upload upto a finished of -2,enable the oxidation style of sulphur be x, there are 4 sulphurs so 4x,oftentimes the oxidation style of oxygen is -2(-a million in peroxides eg: h2o2) so 4x-12=-2 , this skill 4x=+10, this skill x=+10/4 , x=2.5 so for each sulphur atom the oxidation style is two.5 yet oftentimes sulphur exists as s2 so the oxidation style of sulphur(s2) is +5...;)
2016-11-30 11:16:37 · answer #3 · answered by kuebler 4 · 0⤊ 0⤋
When H reacts with metals to form hydrides it has a H-
2006-12-11 13:04:15 · answer #4 · answered by science teacher 7 · 0⤊ 0⤋