how can i slove this math problem? this is my daughters math hw and i forgot how to do it?

Question

there are two questions that i really don't understand if anyone can help, i'd really appreciate it.

1. if one of two complementary angles measures 80*degree, what if the measure of the other?

i know that complementary is 90*degrees but so the other angle would be 10*degree?

and last question is

2. if two supplementary angles are in the ratio of 5:4, find the measure of the larger angle?

hmmm, no cule on this one


thanks guys for all the help

Answer 1

Is your daughter taking trig or what.

first question soundlike are right triangle to me all the angles of a triangle add up to 180 degrees. 80 + 90 = 170 180 - 170 = 10 so you got that right.

my brain is cramping on the second problem but I think it might be 50 degrees and 40 degrees. And I am taking a scientific wild #ss guess on this one.

Answer 2

correct.
the second question. I used algebra. x+y = 180. 5/4=x/y.
so... 5/4y=x plug in x in the first equation. 5/4y +y = 180. Then simplify. add the y's to get 9/5y=180. Then 9y = 720. Then y=80, so x= 100. The angles are 80 and 100!

Answer 3

1.you areright
the other will be 10*
2.let the angles be 5x and 4x
5x+4x=180*
9x=180*
x=20*
therefore the angles are 100* and 80*

Answer 4

You are right in the first question

2)
5 ----------- x
(5+4) ----- 180

x = 5*180 / 9

x = 100º

₢

Answer 5

a*xSquare - b*x - c = 0 D = bSquare - 4*a*c x1 = (- b + SquareRoot D) / 2*a x2 = (- b - SquareRoot D) / 2*a D = (-2)sq. - 4*2*(-a million) = 12 x1 = (- (-2) + SquareRoot (12)) / 2*2 = (a million+ SquareRoot 3)/2 = 0.5 + (SquareRoot 3)/2 x2 = (- (-2) - SquareRoot (12)) / 2*2 = (a million- SquareRoot 3)/2 = 0.5 - (SquareRoot 3)/2