THe offspring of two short tailed cats have a 25% chance of having no tail, a 25 % chance of having a long tail, and a 50% chance of having a short tail. Based on this information, what can you hypothesize about the genotypes of the parents?
2006-12-11 12:32:09 · 7 answers · asked by rock 1 in Science & Mathematics ➔ Biology
They are both heterozygous. For two heterozygotes, out of every four children they have, you would get one AA (long tail), two Aa (short tail), and one aa (no tail).
2006-12-11 12:34:07 · answer #1 · answered by Peeps 3 · 0⤊ 0⤋
The parents are both heterozygous Tt (short tail). Homozygous TT will give a long tailed cat. Homozygous recessive tt will give a no tail.
Parents Tt X Tt probable offspring 1 TT long tail 2 Tt short tail, 1tt no tail
2006-12-11 20:42:40 · answer #2 · answered by john h 7 · 0⤊ 0⤋
I would guess that they are heterzygous for a gene that in heterozygous individuals shortens the tail, and in homozygous individuals removes it completely. The parents are both Tt, and their kids have a 1/4 chance each of being TT or tt, and a 1/2 chance of being Tt.
2006-12-11 20:34:36 · answer #3 · answered by Amy F 5 · 1⤊ 0⤋
If (TT) is a long tail, (Tt) is a short tail, and (tt) is no tail, then the parents should be both (Tt). Did your teacher ever teach you the Punnett square method? it's very useful.
2006-12-11 20:36:16 · answer #4 · answered by CJ 2 · 0⤊ 0⤋
on war was full long tail
and one was half no tail.
2006-12-11 20:34:47 · answer #5 · answered by Trash Master 1 · 0⤊ 0⤋
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2006-12-11 20:33:23 · answer #6 · answered by lori b 2 · 0⤊ 2⤋
doesnt biology suck!?!?!?! lol i know! i hate it lol
2006-12-11 20:33:21 · answer #7 · answered by ajhkgfhjdfgksj 5 · 0⤊ 0⤋