this doesnt make sense. Na is 1+ and you add it to 2Cl 1-.???
2006-12-11 12:24:25 · 4 answers · asked by THE ICE AGE 2 in Science & Mathematics ➔ Chemistry
This is a double replacement rxn. The problem you mention will be resolved once the rxn is balanced. At first, you just worry about oxidation numbers. Then you balance.
2NaOH + CoCl2 ------> 2NaCl(aq) + Co(OH)2(s)
The cobalt (II) hydroxide will precipitate
2006-12-11 12:29:14 · answer #1 · answered by Math-Chem-Physics Teacher 3 · 0⤊ 0⤋
You should balance the equation, and make sure every reagent and product is zero charge
2 NaOH + CoCl2--> 2 Na Cl + Co(OH)2
Cobalt is positive 2 charge, whereas hydroxide is negative 1 charge, that's why the last product is Co(OH)2
Cl (Chloride) is negative 1 charge, that's why it has to be CoCl2.
That's why you need to memorize the charge of the element(Periodic Table is a helpful tool )
2006-12-11 12:34:34 · answer #2 · answered by afortunado 2 · 0⤊ 0⤋
You have to balance the equation. It's 2NaOH + CoCl2 --> 2NaCl + Co(OH)2. You use two moles of NaOH for each mole of CoCl2, so there are enough Na's to balance the Cl's.
2006-12-11 12:27:40 · answer #3 · answered by Amy F 5 · 0⤊ 0⤋
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NaOH + CoCl2 ------> ??
this doesnt make sense. Na is 1+ and you add it to 2Cl 1-.???
2015-08-24 05:52:13 · answer #4 · answered by Lola 1 · 0⤊ 0⤋
the balanced equation if this is a double displacement reaction will be
2NaOH + CoCl2 --> 2NaCl + Co(OH)2
2006-12-11 12:27:56 · answer #5 · answered by Peter W 2 · 0⤊ 0⤋
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2NaOH + CoCl2--->2 NaCl +Co(OH)2
2016-04-02 09:33:37 · answer #6 · answered by Pamela 4 · 0⤊ 0⤋