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From what height ( in meters) must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of an oxygen molecule at 300 K?

2006-12-11 12:08:03 · 1 answers · asked by physicsmed22 1 in Science & Mathematics Physics

1 answers

the energy of a molecule after falling from height h=mgh so
mgh=<1/2 mv2> and
3/2 kT = <1/2 mv2>
k is Boltzmann’s constant, k = 1.38 x 10-23 JK-1(molecule)-1

2006-12-11 15:02:04 · answer #1 · answered by meg 7 · 1 0

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