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The Line that passes through (-2,-3) and is perpendicular to the line y=-1

2006-12-11 12:05:51 · 11 answers · asked by . 1 in Science & Mathematics Mathematics

11 answers

y=y-co-ord
x=x-co-ord
m=slope
b=y-int
y=mx+b
slope(m) is perp -1, m is the opposite recipricle, => m= 1/-1 (up one, over neg one.)

y=mx+b
-3=1/-1(-2)+b(where line hits y-axis)

2006-12-11 12:36:27 · answer #1 · answered by lolavonb 2 · 0 0

When two lines are perpendicular, that means the slopes are opposite reciprocals of one another and meet at a 90 degree angle. However, y = -1 has a slope of zero, so this line is a horizontal line. The line your looking for has to be a vertical line, which will indicate the slope is undefined (opposite reciprocal of 0 = -1/0). A straight vertical line that passes through the point (-2,3) can only be the line x = -2.

2006-12-11 12:15:43 · answer #2 · answered by Ohhboy! 1 · 0 0

x = -2

2006-12-11 12:17:21 · answer #3 · answered by Helmut 7 · 0 0

Ok so the line y = -1 is horizontal so if the line u want is perpendicular to that it will be vertical

and this means that it will pass though every value of y but we only want it to pass though one value of x , -2

So for any value of y, x= -2
x = -2

2006-12-11 12:16:31 · answer #4 · answered by Anonymous · 0 0

Lines thta are perpindicular to each other have slopes that are reciprocals of each other and opposite in sign....normally, but here you are dealing with two lines that neither of which has slope per se.

A line y = -1 is a horizontal line.

The perpindicular line to that has to be vertical and it HAS to be:

x = -2

With x = -2 by default it MUST pass thru y = -3 which is part of the requirement given in the problem.

Luiz got it before I did....please give him the 10 points. :)

2006-12-11 12:15:38 · answer #5 · answered by Anonymous · 0 0

put it in y=mx + b form then when you plug in the cordinates it should look like this

-3 = 1(-2) + b then
-3 = -2 + b
+2 +2 then
1= b


hope that helps you :-)

2006-12-11 12:16:13 · answer #6 · answered by Anonymous · 0 0

are you sure it's not a trick question?

if something is perpendicular to a horizontal line, then that line has an undefined slope (i.e., it goes straight up and by math definitions, its slope is undefined because it technically doesn't have one)

or maybe there's more info you neglected to give

2006-12-11 12:12:24 · answer #7 · answered by (+_+) B 4 · 0 1

y = -1 => y = 0x-1

Perpendicular to y = -1 is:
x = k

And k = -2

So the equation is:

x = -2

2006-12-11 12:10:39 · answer #8 · answered by Luiz S 7 · 1 0

x=1 is the slope
use point-slope form so..
y-(-3)=1(x-(-2))
y+3=x+2
y=x-1

i think

2006-12-11 12:10:01 · answer #9 · answered by ciaobella492 1 · 0 1

line equation- x=-2

im positive

2006-12-11 12:16:32 · answer #10 · answered by Anonymous · 0 0

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