Chemistry HelPPP!!!!?

Question

Please Help:

93.0 ml of 0.150 M magnesium hydroxide is added to 57.0 ml of 0.4 nitric acid. Magnesium nitrate and water are formed. What is the concentration of the magnesium nitrate after the reaction.

Answer 1

Mg(OH)2 + 2HNO3 -> Mg(NO3)2 + 2H2O

# moles Mg(OH)2 = 0.0930 * 0.150 = 0.01395 moles
# moles HNO3 = 0.0570 * 0.4 = 0.0228 moles

limiting reactant is HNO3

so # moles of Mg(NO3)2 = 0.0114 moles

so concentration of Mg(NO3)2 = 0.0114 / (0.0930 + 0.057)
= 0.076