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A lottery machine uses blowing air to keep 2000 Ping-Pong balls bouncing around inside a 1.0m x 1.0m x 1.0m box. The diameter of a Ping-Pong ball is 3.0 cm. What is the mean free path between collisions?
Give your answer in cm.

2006-12-11 11:57:11 · 2 answers · asked by MattS 1 in Science & Mathematics Physics

2 answers

mean free path=1/(sqrt(2)pi d^2 n)
the number per unit volume is n=2000/m^3
see for details
http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/menfre.html

2006-12-11 15:13:35 · answer #1 · answered by meg 7 · 2 0

1/[sqrt(2)*pi*2000*(.03)^2]=12.5 cm

2015-11-17 10:51:41 · answer #2 · answered by Kate 1 · 1 0

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