Help. I follow this problem except for one very big problem. How is it that .01490 turns into 0.149?
200.0 J of heat is required to raise the temperature of an object by 3.00 C. If the specific heat of the object is .01490 J/gC... what is the mass of the sample?
I understand that I have to solve for mass and therefore isolate it.
Therefore:
200.0 = ____ x .01490 x 3.00C
200 = M(0.149)(3)
From there, I understand that 200 = 0.447
But I do NOT understand how .01490 becomes 0.149.
2006-12-11 11:38:19 · 2 answers · asked by ♥ Mommy To Be 12/20/09 ♥ 3 in Science & Mathematics ➔ Chemistry
Based on your numbers and the given info, that 0.149 seems to me a typo.
2006-12-11 11:41:29 · answer #1 · answered by Math-Chem-Physics Teacher 3 · 0⤊ 0⤋
Hi,
It is fine that the sp. heat of object is 0.0149joules/gramdegc.
Let it be like that.
Now, if you calculate for mass it will come about 4474.27 grams and 4.47kg!
2006-12-12 15:47:19 · answer #2 · answered by Krishna 1 · 0⤊ 0⤋