The asteroid Ceres has a mass of 7.0 * 10^20 kg and a radius of 500 km.
a. What is the gravity on the surface of Ceres?
b. How much would a 90-kg astronaut weigh on Ceres?
Please help me with this problem.
I'm having trouble understanding it.
2006-12-11 11:27:57 · 2 answers · asked by vicky p 1 in Science & Mathematics ➔ Physics
We need to use Fg = G*m*M/d^2
To get the gravity, we assume a 1kg object on the surface of Ceres.
Fg = (6.67 * 10^-11) * (1) * (7.0 * 10^20) / (5 *10^5)^2
= 0.19 N
A 90kg person on Ceres will weigh
w = m * g
= 90 * 0.19
=17 N
2006-12-11 11:36:40 · answer #1 · answered by Math-Chem-Physics Teacher 3 · 0⤊ 0⤋
only use the easy gravitation equation and plug interior the right values, previously calculation F = G x M1 x M2 /d ^2 G = 6.sixty seven x 10^-11 N-m^2 / kg^2 M = 8.56 &activities; 10^20 kg. M = sixty 3.a million kg d = 1140 km = 1140000 m
2016-11-30 11:05:03 · answer #2 · answered by Erika 4 · 0⤊ 0⤋