help with adding & subtracting radicals?

Question

i know i should understand this, but i don't.

rad.27 + rad.75?

rad. 72 - rad.50?

3rad.8 - 1rad.2?

3rad.32 - 6rad.8?

3rad.50 - 5rad.18?

does that even make sense?
(sorry there's no wingding for the radical sign)

Answer 1

Actually there is a 'wingding'. You just have to choose the same font that you're using here, and then look thu the symbols. It's there. I'm impressed that you even had a clue on that part! cool man

As for the math stuff.....some of them you can't really do anything with. Like the first one......nothin' is gonna combine with √27.

As for the others, you just have to look and see if tyhere is some perfect square that you can remove from under the radical sign so you get the same radicand.

Like the third one for example.

3√8 - 1√2

Well...√8 - 2√2..........yes?? √8 = √(2*4) - √4*√2 = 2√2

==> 3(√8) = 3(2√2) = 6√2
==> 6√2 - 1√2
==> 6√2 - √2
==> 5√2

(done)

See?

Here's a hint for #1: √(9*3) + √(25*3) = √8*√3 + √25*√3

K.....you try the rest for yourself. Learn.......think at least. :)

Try the others....if you can't get them, send me a message and I will help you on the rest..........ok?

This stuff isn't hard. It's just a puzzle. Follow the rules and play and have fun with it.

Answer 2

1. rad.27 +rad.75 = 3rad.3 + 5rad.3=8rad.3
2. rad. 72 - rad.50 = 6rad.2 - 5rad.2 = 1rad.2 =rad.2
3. 3rad.8 - 1rad.2 = 3x2rad.2 -1rad.2 = 6rad.2- 1rad.2 = 5rad.2

Answer 3

1. reduce rad. 27 to 3rad.3 and rad.75 to 5rad.3, add five and three so your answer is 8rad. three
2. reduce rad.72 to 6rad. 2 and rad.50 to 5rad.2, subtract six and five to get just rad.2.
3. reduce 3rad.8 to 6rad.2 and subtract with 1rad.2 to get 5rad.2
not completely sure about the other two because the answers come out to be 0rad.2 for both and i dont know if that is possible...email me if you have more questions, good luck

Answer 4

You must factor each radical into its largest perfect square and the other number so 27 would be 9 and 3; 75 would be 25 and 3. The square root of 9*3 is 3radical3 and the square root of 75 is 5 radical 3. You add and subtract radicals similarly to x's and y's by adding and subtracting the coefficients so the final answer to your first example is:

8radical3

The others follow similarly

radical2
5radical2
0 (they're both 12radical2)
0 (they're both 15radical 2)

Answer 5

What you want to do is cut back the sqrt's to being a similar. as an social gathering, Sqrt(18) = sqrt(2 * 9) = sqrt(9) * sqrt(2) = 3 sqrt(2) so, your first expression will become 4 * sqrt(2) + 18 * sqrt(2) = 22 * sqrt(2) the 2d one works in a similar way (40 8 = 16 * 3 and seventy 5 = 25 * 3 ==> 16 = 4^2 and 25 =5^2) so 5 * 4 * sqrt(3) - 4 * 5 sqrt(3) = 0

Answer 6

simply the radicals as much as possible
ex. rad27 = rad3 x rad9 = rad3 x 3
rad75 = rad25 x rad3 = 5 x rad3

the radicals know have a common radical of rad3
3 x rad3 + 5 x rad3 = rad3 x (3 + 5)

so the radical is
rad3 x 8

=)

if you understand this, i will help with the other ones. =)

Answer 7

8rad.3
rad.2
5rad.2
0
0