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1. n=5, 1=2, m2=0, ms=1/2
2. n=3, 1=2, m1=0, ms=1/2
3. n=4, 1=2, m1= -1, ms= -1/2
4. n=4, 1=1, m1=0, ms = -1/2

2006-12-11 10:56:31 · 1 answers · asked by csu0811 1 in Science & Mathematics Chemistry

1 answers

4 is the ground state configuration, with an electron in one of the 4p orbitals. 1 and 3 would be excited state configurations, with an electron in either in one of the 5d or one of the 4d orbitals. 2 is one of the 3d orbitals, which would not be for the outermost electron.

2006-12-11 11:20:06 · answer #1 · answered by TheOnlyBeldin 7 · 0 0

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