Three numbers added together total 500. The second number is four times the first, and the third is five times the second.
I cant come up with an equation to solve this.
2006-12-11 10:53:10 · 6 answers · asked by grem 3 in Education & Reference ➔ Homework Help
ive got the answers just need it spelled out =)
2006-12-11 11:01:04 · update #1
1. x + y + z = 500
2. y = 4x
3. z = 5y
2. x = y/4
substituting 2 and 3 into 1 gives
y/4 + y + 5y = 500
multiply by 4
y + 4y + 20y = 2000
25y = 2000
y=2000/25 = 80
substituting y into 2 ( x= y/4)
x = 80/4 =20
substituting y into 3 (z=5y)
z = 80 x 5 = 400
2006-12-11 11:08:58 · answer #1 · answered by adam_adams_25 3 · 1⤊ 0⤋
The equation you are looking for is:
x+4x(the second number is 4 times the first)+5(4x)(the third is 5 times the second)=500
x+4x+5(4x)=500
x+4x+20x=500
25x=500
x=20
Work it backwards:
20+4*20+5(4*20)=500
20+80+400=500
2006-12-11 19:02:39 · answer #2 · answered by joatradesaz 2 · 0⤊ 0⤋
the first number is 50, second 200 third 250. when added together gives 500.
2006-12-11 18:56:39 · answer #3 · answered by rashmir 2 · 0⤊ 1⤋
x = 1st number
y = 2nd number
z = 3rd number
three equations:
x + y + z = 500
y = 4x
z = 5y
to solve pulg in y and z in equation
2006-12-11 19:02:31 · answer #4 · answered by !!!!!! 3 · 0⤊ 0⤋
25x4x5=500
2006-12-11 19:03:51 · answer #5 · answered by munkeybuiznez 1 · 0⤊ 1⤋
easy
x + y + z =500
y = 4x
z = 5y
x=20
y=80
z=400
2006-12-11 18:58:08 · answer #6 · answered by Anonymous · 1⤊ 0⤋