There is a relative maximum or relative minimum at each critical number. if false explain please
2006-12-11 10:47:03 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
That is false.
Consider the function f(x) = x^3
Then, f'(x) = 3x^2
And we solve for critical numbers by making f'(x) equal to 0.
0 = 3x^2
0 = x^2
Therefore, x = 0
However, f(x) is increasing from (-infinity, infinity), and
f(0) = 0 is not a relative maximum or minimum.
2006-12-11 10:53:12 · answer #1 · answered by Puggy 7 · 0⤊ 0⤋
Consider the function x^3.
2006-12-11 18:48:58 · answer #2 · answered by Sean H 5 · 0⤊ 0⤋
If you want to find rel. max or min that u have to find critical number first.
2006-12-11 18:53:27 · answer #3 · answered by Rockie 1 · 0⤊ 0⤋
I know nothing about calculus
2006-12-11 18:49:50 · answer #4 · answered by Jake D 1 · 0⤊ 0⤋