math
2006-12-11 10:27:10 · 10 answers · asked by Mayra M 1 in Science & Mathematics ➔ Mathematics
24=3(2r-2)+4r
24=6r-6+4r
30=10r
r=3
2006-12-11 10:29:03 · answer #1 · answered by anonymousperson 4 · 0⤊ 0⤋
24=3(2r-2)+4r
24 = 6r - 6 + 4r (distribute 3 to the numbers in parenthesis)
24 + 6 = 6r + 4r (combining similar tems)
30 = 10r
3 = r (dividing 10 to both sides)
Checking: (replace all r by 3)
24 = 3[2(3)-2] + 4(3)
24 = 3[6-2] + 12
24 = 3[4] +12
24= 12 + 12
24 = 24
2006-12-11 10:37:44 · answer #2 · answered by racz_jay25 2 · 0⤊ 0⤋
24 = 3(2r - 2) + 4R
24 = 6r - 6 + 4r
24 = 10 r - 6
24 + 6 = 10r - 6 + 6
30 = 10r
30/10 = 10r/10
3 = r
The answer is r = 3
Insert the r value into the equation
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Check
24 = 3(2r - 2) + 4r
24 = 3[2(3) - 2] + 4(3)
24 = 3[6 - 2] + 12
24 = 2[4] + 12
24 = 8 + 12
24 = 24
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2006-12-11 10:41:35 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
r=3
2006-12-11 10:31:22 · answer #4 · answered by lenshure 2 · 0⤊ 0⤋
24=3(2r-2)+4r
24=6r-6+4r (multiply the brackets by 3 then remove brackets)
24=10r-6 (add the common numbers together the r's in this case)
30=10r (add 6 to both sides to remove the -6 and get the R value alone)
r=3 (divide both sides by 10 to get r alone and reveal your answer)
So R = 3 in this equation
2006-12-11 10:32:29 · answer #5 · answered by bheithcao 2 · 0⤊ 0⤋
24=6r-6+4r
10r=30
r=30/10
=3
2006-12-11 10:29:38 · answer #6 · answered by raj 7 · 0⤊ 0⤋
24=3(2r-2)+4r
24=6r-6+4r
24=10r-6
10r=24+6
10r=30
r=3
2006-12-11 10:30:09 · answer #7 · answered by Anonymous · 0⤊ 0⤋
24=3(2r-2)+4r
24=6r-6+4r
24=10r-6
30=10r
*r=3*
2006-12-11 10:30:08 · answer #8 · answered by One With No Name 2 · 0⤊ 0⤋
24=10r-6
30=10r
3=r
2006-12-11 10:36:02 · answer #9 · answered by Courtney 2 · 0⤊ 0⤋
I guess I'll say r=3 also.
2006-12-11 10:39:08 · answer #10 · answered by Bob N 2 · 0⤊ 0⤋