2.00 g of gaseous HCl are dissolved in water to give a final solution of 29.0 mL .?

Answer 1

You want to know what is the molarity of the HCl solution?

2.00gHCl/29.0mlSoln x 1molHCl/36.5gHCl x 1000mLSoln/1LSoln = (2.00)(1000)/(29)(36.5) = molHCl/L HCl

Molarity is moles per liter, L. That is a two-part answer. So you must begin with a two-part given, the 2.00gHCl and the 29.0mL solution. In the first step, the gHCl cancel to yield molHCl. In the second step, the mL soln cancel to yield the L soln.