expand Log base 2 (3x)?

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2006-12-11 09:53:50 · 4 answers · asked by Porcel18 1 in Science & Mathematics ➔ Mathematics

Expand Log base 4 (6/5)

2006-12-11 09:59:45 · update #1

log(ab) = log(a) + log(b)

So,

log[2](3x) = log[2](3) + log[2](x)

You can solve for log[2](3) using log(3) / log(2), if you want to.

2006-12-11 09:56:35 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋

That could be rewritten as
Log base 2(3) + Log base 2(x)

that's following the identity
log(a*b) = log(a) + log(b)

2006-12-11 17:58:10 · answer #2 · answered by gjensidige4 1 · 0⤊ 0⤋

log base 2 (3x) = log(3x)/log2.

2006-12-11 17:55:35 · answer #3 · answered by Anonymous · 0⤊ 0⤋

log2(3) + log2(x)

2006-12-11 17:56:44 · answer #4 · answered by Anonymous · 0⤊ 0⤋