How do you graph 3x+2y=5 on a Cartesan Plane?

Answer 1

Either pick a value for x and solve for y or vice versa. Do this for several values, then connect those points. This is a linear equation so it will be a line.

A couple easy choices are x = 0 or y = 0. For x = 0, y = 2.5 and for y = 0, x = 1.6667

Now plot the two points (0, 2.5) and (1.6667, 0) and connect.

Alternatively, put the formula in slope-intercept, by solving for y:
2y = 5 -3x
y = (5-3x)/2

No get it so it looks like y = mx + b
y = -(3/2)x + 5/2

This would be a line through (0, 5/2) with a downward slope of -3/2... (rise = -3, run = 2)

Either way the final graph should look like the attached graph.

Answer 2

In standard form there are three simple formulas for x-intercept, y-intercpet (b), and slope (m). In Ax+By=C:
Slope= -A/B
Y-intercept= C/B
X-intercept=C/A
So if it is 3x+2y=5, find the X-intercept (5/3) and the Y-intercept (5/2), plot and then commect the points. OR you can do it by finding the Y-intercept(5/2) and then use the slope(-3/2) to find anphter point. (Using rise over run). From (5,2) go down 3 spaces and 2 to the right. Connect, and carry on the line.

Answer 3

You can solve for y for
y=(-3/2)x + 5/2 and set x=0, then y=5/2
then solve for x for
x=(-2/3)y + 5/3 and set y=0, then x=5/3

This means the x intercept 5/3 and the y intercept 5/2
Put a dot on both points and draw a line thru them.