The area of the base of Cylinder A is 4 times the area of the base of Cylinder B. What is the radius of Cylinder A (rA) in terms of the radius of Cylinder B (rB)?
A. rA=rB
B. rA=4(rB)
C. rA=2(rB)
D. rA=(rB)/4
E. rA=(rB)/2
Please Explain.
2006-12-11 09:11:35 · 5 answers · asked by Jamaal 5 in Science & Mathematics ➔ Mathematics
So what you're saying is
pi(rA)^2=4pi(rB)^2
(rA)^2=4(rB)^2 [Divide each side by pi]
rA=2(rB) [Take the square root of each side]
So it would be C.
2006-12-11 09:18:52 · answer #1 · answered by anonymousperson 4 · 1⤊ 1⤋
B, if Cylinder A is 4 times the area of the base of Cylinder B, then the area of the base of Cylinder B times 4 is equal to the area of the base of Cylinder A.
2006-12-11 17:22:18 · answer #2 · answered by bob 2 · 0⤊ 0⤋
e
once you multiply the base you have to divide the whole number to get the actual area of the cylinder
2006-12-11 17:14:33 · answer #3 · answered by anonbealove 3 · 1⤊ 1⤋
r(A)=2r(B)
area is a square functionof the radius or radius is the square root function of the area
2006-12-11 17:14:46 · answer #4 · answered by raj 7 · 1⤊ 1⤋
B.
2006-12-11 17:13:55 · answer #5 · answered by ? 5 · 0⤊ 2⤋