How do you do it? This is Stoichiometry.
2006-12-11 08:20:30 · 5 answers · asked by Carrie2007 2 in Science & Mathematics ➔ Chemistry
Approximately 55.85 grams. 1:1 reaction, and you have 1 mole of sulfur, so you need 1 mole of iron.
2006-12-11 08:24:20 · answer #1 · answered by TheOnlyBeldin 7 · 0⤊ 1⤋
Moles S = 32.0g / 32.065 g/mol= 0.998 The ratio is 1:1 so we get 0.998 mole of iron Atomic weight Fe = 55.845 g/mol Weight Fe needed = 0.998 mol x 55.845 g/mol = 55.7 g
2016-03-29 03:34:40 · answer #2 · answered by ? 4 · 0⤊ 0⤋
32.0 g S * 1 mol S / 32.07 g S (multiply by inverse of molar mass) = .998 mol S
.998 mol S * 1 mol Fe / 1 mol S (convert from S to Fe)= .998 mol Fe
.998 mol Fe * 55.85 g Fe / 1 mol Fe (multiply by molar mass) = 55.73 g Fe
2006-12-11 08:31:14 · answer #3 · answered by Peter 2 · 0⤊ 0⤋
Fe + S ---> FeS
this is a massA-->molA-->molB--->massB
type problem
start with the given
?g Fe = (32.0gS)x
convert to moles A (formula mass)
[(1mol S)/(32.07g S)]x
convert to moles B with bal equation
[(1mol Fe)/(1mol S)] x
convert to mass B (formula mass)
[(55.85gFe)/(1mol Fe)] = 55.7g Fe
2006-12-11 08:32:14 · answer #4 · answered by rm 3 · 0⤊ 0⤋
he's right, 55.8 (or whatever he said) is the right answer
2006-12-11 08:29:02 · answer #5 · answered by ccmfreak101 2 · 0⤊ 0⤋