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if you have 0.5 mol glucose (C6H12O6) in 1000g H2O?

2006-12-11 07:40:14 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

or 1.5 mol NaCl in 1000 g water?

2006-12-11 07:51:02 · update #1

1 answers

Delta T = Kb * m = 0.52 * 0.5 = 0.26 (m is molality, which for this is 0,.5 moles solute in 1 kg solvent or 0.5)

BP = 100.26

For NaCl, you have to include the van't Hoff factor, which for NaCl is 2.

delta T = 2 Kb * m = 2 * 0.52 * 1.5 = 1.56

BP = 101.56

2006-12-11 07:51:11 · answer #1 · answered by TheOnlyBeldin 7 · 0 0

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