Need this maths equation answered with working please...?

Question

ttpo = to the power of
2x ttpo 1/2 (x ttpo 1/2 - x ttpo -1/2)

Hope you understand that...

Answer 1

2x^(1/2) *x^(1/2)-2x^(1/2)x^(-1/2)
=2*x^(1/2+1/2)-2x^(1/2-1/2) [a^m*a^n=a^(m+n)]
=2x^1-2x^0 (a^0=1)
=2x-2
=2(x-1)

Answer 2

I'll use ^ for ttpo

I assume you just want this simplified:

(2x)^(1/2) * ( x^(1/2) - x^(-1/2))

well, let's get everything at the same base first:
sqrt(2) * x^(1/2) * ( x^(1/2) - x^(-1/2) )

now distribute:

sqrt(2) * x^(1/2) * x^(1/2) - ( sqrt(2) * x^(1/2) * x^(-1/2) )

multiplying x^a * x^b = x^(a+b)

sqrt(2) * x^1 - sqrt(2) * x^0 = sqrt(2) * x - sqrt(2) or

sqrt(2) ( x - 1 )

Answer 3

2x^(1/2)(x^(1/2) - x^(-1/2))
= 2x^(1/2) x^(1/2) - 2x^(1/2) x^(-1/2)
= 2x^(1/2+1/2) - 2x^(1/2-1/2)
= 2x^1 - 2x^0
= 2x - 2 ------- because x^0 = 1
= 2(x-1)

Answer 4

I understand that you can't be arssed to do it yourself