how would u make a solution with mole fraction...?

Question

describe how you would make an aqueous solution of methanol (CH3OH) in which the mole fraction of methanol is 0.40.

Answer 1

If the mole fraction of methanol is 0.40, then that of water is 0.60. For methanol, MW is 32, so you would have 12.8 grams. For H2O, it's 18, so you would have 10.8 grams. 10.8 grams of water (roughly 1 g/ml) would be 10.8 ml. Density of methanol being approximately 0.79, 12.8 grams would occupy 16.2 ml.

So for every 16.2 ml of methanol, you would need 10.8 ml of water. Multiply by 5 to make them whole numbers and you would need 81 ml methanol for every 54 ml of water.