A 2 ton UPS truck descending a 5 degree hill is brought to a stop at 250 ft. The driver applies the brakes so that the wheels lock. A) If the coeffiecient of kinetic friction between the truck tires and the road is 0.60, how much work in Joules is done by the force of friction in stopping the truck? B) How much work is done on the truck by gravity??
2006-12-11 07:12:26 · 2 answers · asked by Tennis2127 2 in Science & Mathematics ➔ Physics
force of friction is=cof of friction* mass* 9.81m/s2
work done= force * disp
and remember the trucks on the 5 deg hill so use trigo to find the actual displacement
2006-12-11 08:07:31 · answer #1 · answered by questinme 1 · 0⤊ 0⤋
First step, convert all units to SI units. I don't know why you would be given in problem with this unit system. That will probably help you work out the answer.
2006-12-11 15:43:13 · answer #2 · answered by msi_cord 7 · 0⤊ 0⤋