Bob has 27 out of 30 problems correct on an English test. What was his percent of correct problems?
2006-12-11 07:08:16 · 10 answers · asked by ♥ 6 in Science & Mathematics ➔ Mathematics
90% -- 27/30 = 9/10 = 90%
2006-12-11 07:10:34 · answer #1 · answered by Justin B 2 · 0⤊ 0⤋
90%.
27 correct / 30 total problems X 100 to make it a percent.
2006-12-11 15:11:59 · answer #2 · answered by donfajn2 1 · 0⤊ 0⤋
27/30 = 9/10 = 90%
2006-12-11 15:11:09 · answer #3 · answered by Anonymous · 0⤊ 0⤋
27 / 30 * 100 = 90%
2006-12-11 15:10:47 · answer #4 · answered by Ronald B 2 · 0⤊ 0⤋
27/30=.9=90%
2006-12-11 16:13:20 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋
27/30 = x/100
270/3 = x
x = 90%
2006-12-11 15:14:57 · answer #6 · answered by S. B. 6 · 0⤊ 0⤋
Twenty-seven divided by thirty times a hundred. 27/30X100=90% His percent of correct problems was 90.
2006-12-11 15:11:33 · answer #7 · answered by athletic_dude03 1 · 0⤊ 0⤋
I think it's 90%
2006-12-11 15:10:40 · answer #8 · answered by Mrs.Vengeance 6661!!! 2 · 0⤊ 0⤋
you divde the numbers so its 27/ 30. but i don't have a calculator so i can't tell you the answer.sorry.
2006-12-11 15:17:45 · answer #9 · answered by Ruby 1 · 0⤊ 0⤋
It is a proportion. the answer is 90%
2006-12-11 15:10:49 · answer #10 · answered by A7X Girl 3 · 0⤊ 0⤋