A grocery store has 192 oranges for sale . Half-way through a week the grocery store buys 157 oranges and by the end of the same week has only 77 oranges remaining. How many oranges were taken from the most recent order if the older oranges were sold first?
2006-12-11 07:03:50 · 9 answers · asked by donfajn2 1 in Science & Mathematics ➔ Mathematics
157-77=80. 80 oranges were sold from the most recent order. You're right, very easy math problem.
2006-12-11 07:09:29 · answer #1 · answered by athletic_dude03 1 · 0⤊ 0⤋
Ok, you start with 192 and a week later you had sold all of those.
192 Bought
192 Sold
0 Remaining
Halfway thru the week, you buy 157 oranges and by the end of the week you have 77.
157 Bought
? Sold
77 Remaining
I would say that 80 oranges were sold from the second batch.
2006-12-11 07:08:54 · answer #2 · answered by A.Mercer 7 · 0⤊ 0⤋
80.
If there are only 77 oranges left, all the old oranges were sold and there were 157 - 77 = 80 oranges sold from the new order.
2006-12-11 07:08:54 · answer #3 · answered by Ronald B 2 · 0⤊ 0⤋
192+157=349
349-77=272
272-192=80
so 80 oranges left as mentioned by the others too...
This was supposed to be hard?
2006-12-11 07:34:24 · answer #4 · answered by ... 2 · 0⤊ 0⤋
(192+157)-(192+x) = 77
-(192+x) = 77-349
-192-x = -272
-272+192 = -x
-80 = -x
x = 80
2006-12-11 07:18:17 · answer #5 · answered by GABE_1 2 · 0⤊ 0⤋
80
2006-12-11 07:15:55 · answer #6 · answered by SMLP 2 · 0⤊ 0⤋
perceive the answer set of the inequality, utilising the given alternative set. x < –4; {–10, –4.3, –4, –3.9, 2, 6.5} evaluate a style line. go with all values a lot less that -4 ( to the left of -4) C. {–10, –4.3} remedy. 3y + 15 > –6 3y +15 -15 > -6 -15 3y > -21 3y/3 > -21/3 y > -7 ////// B remedy. -s/3 >= 6 3 * -s /3 >= 3*6 -s >= 18 s <= -18 ///// D
2016-11-30 10:47:02 · answer #7 · answered by ? 4 · 0⤊ 0⤋
80 taken from the new ones.
2006-12-11 07:08:32 · answer #8 · answered by youngxboxmale 1 · 0⤊ 0⤋
80?
2006-12-11 07:08:08 · answer #9 · answered by Anonymous 1 · 0⤊ 0⤋