equation of a line through (3,-4) and (5,8)?

Answer 1

Slope:
m=(y2-y1)/(x2-x1)
m=(8+4)/(5-3)
m=12/2=6

Here's the next formula:
(y-y1)=m(x-x1)
y+4=6(x-3)
y+4=6x-18
y=6x-22

Check:
-4=6(3)-22
-4=18-22
-4=-4

8=6(5)-22
8=30-22
8=8

Answer 2

general form of the equation of a line is y= mx +c
m = (8- -4)/(5-3) =12/2
=6
y = 6x + c
8 = 6*5 +c
c =8-30 = -22
therefore the equation is y = 6x-22 Ans.

Answer 3

slope = (8 - -4 ) / ( 5 - 3 ) = 12 / 2 = 6

Y = mX + b

Y = 6X + b solve for one of the points
-4 = 6(3) + b
-22 = b

Y = 6X - 22 // check the other point
8 = 6(5) - 22
8 = 8 // check.


Answer: Y = 6X - 22

Answer 4

we write that the line y =ax+b goes through these points

-4 = 3a+b (1)

8 = 5a +b (2)

solve the system
(1) - (2) yields -12 = -2a

hence a=6 b= -22

y =6x -22 you can verify

Answer 5

answer is y = 6x- 22

solution
y -y1 = m(x-x1)

m= change in y over change in x
m = (8--4)/(5-3) = 12/2 = 6

put numbers in for variables y1 & x1 & m

y - -4 = 6(x-3)
y - -4 = 6x - 18
y = 6x -22

Answer 6

8-(-4) / 5-3
12/2=6
-4=6(3)+b
-4=18+b
b= -22
y=6x-22