2006-12-11 05:39:03 · 8 answers · asked by styles4u 4 in Science & Mathematics ➔ Mathematics
You simply group the terms in x squared together, the terms in x together and the constants together:
(5x² - 3x - 9) + (2x² - 7x + 4) =
5x² + 2x² - 3x - 7x - 9 + 4 =
7x² - 10x - 5
2006-12-11 05:45:49 · answer #1 · answered by deedsallan 3 · 0⤊ 0⤋
(5x^2-3x-9) + (2x^2-7x+4)=5x^2+2x^2 -3x -7x -9 +4
=7x^2 - 10x- 5
2006-12-11 13:49:16 · answer #2 · answered by ATS 2 · 0⤊ 0⤋
You have to group like terms. 5x^2 + 2x^2 - 3x - 7x - 9 + 4
So you get 7x^2 - 10x -5
2006-12-11 13:41:21 · answer #3 · answered by sandman72986 2 · 0⤊ 0⤋
add the like terms, so (5x^2 + 2x^2), (-3x - 7x), and (-9 + 4) are each added separately, and you get (7x^2 - 10x -5)
2006-12-11 13:40:46 · answer #4 · answered by Liz S 2 · 0⤊ 0⤋
(5x^2 - 3x - 9) + (2x^2 - 7x + 4) = 7x^2 - 10x - 5
QED
2006-12-11 14:15:32 · answer #5 · answered by CSUFGrad2006 5 · 0⤊ 0⤋
recombine all the like terms:
7x^2 -10x - 5 = 0
now, you have one quadratic, so solve it with the quadratic formula:
roots =
1. (-b + Sqrt(b^2 - 4ac)) / 2a
2. (-b - Sqrt(b^2 - 4ac)) / 2a
so, a is 7 above,
b is 10
c is 5.
This might result in imaginary roots, but that's the way things go sometimes. There you go!
2006-12-11 13:42:35 · answer #6 · answered by otis_hobson 3 · 0⤊ 0⤋
= 7x^2-10x-5
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2006-12-11 13:46:05 · answer #7 · answered by Anonymous · 0⤊ 0⤋
collect the like terms. put the squares with the squares, ect.
2006-12-11 13:41:51 · answer #8 · answered by Ray 5 · 0⤊ 0⤋