2006-12-11 04:51:57 · 9 answers · asked by styles4u 4 in Science & Mathematics ➔ Mathematics
Expand out each using FOIL (First, Outer, Inner, Last), then add them together again...
(4x + 1)² = (4x + 1)(4x + 1)
First: (4x)² = 16x²
Outer: 4x
Inner: 4x
Last: 1² = 1
= 16x² + 8x + 1
(3x - 7)² = (3x - 7)(3x - 7)
First: (3x)² = 9x²
Outer: -21x
Inner: -21x
Last: 49
= 9x² - 42x + 49
Adding these together:
= 16x² + 8x + 1 + 9x² - 42x + 49
Group like terms:
= 25x² - 34x + 50
Unfortunately, this won't factor any further using integer coefficients, so I would consider this the simplified form.
= 25x² - 34x + 50
2006-12-11 04:53:37 · answer #1 · answered by Puzzling 7 · 1⤊ 0⤋
hello This requires three ( 3 ) steps
step 1 :expand the equations
( 4x + 1 )^2 + ( 3x - 7 ) ^ 2
( 4x + 1 )(4x + 1 )
= 16^2 + 4x + 4x + 1
= 16x^2 + 8x + 1
step 2 :
( 3x - 7 )( 3x - 7 )
= 9x^2 - 21x -21x + 49
= 9x^2 - 42x + 49
step 3 :
16x^2 + 8x + 1
+ 9 x^2 - 42x + 49
------------------------------
25X^2 - 34x + 50
2006-12-11 05:08:19 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(4x + 1)^2 = (4x + 1)(4x + 1) = 16x^2 + 8x + 1
(3x - 7)^2 = (3x - 7)(3x - 7) = 9x^2 - 42x + 49
So:
(4x + 1)^2 + (3x - 7)^2
= 16x^2 + 8x + 1 + 9x^2 - 42x + 49
= 25x^2 - 34x + 50
2006-12-11 04:55:42 · answer #3 · answered by claudeaf 3 · 0⤊ 0⤋
the entire suggestion behinds this challenge is 0 multiply with something decision is continually equivalent 0. in this challenge, assume there are 2 numbers multiplying at the same time and their product is 0. therefore, both between both decision must be 0. 9x - 8 = 0 x = 8/9 or 8x + 2 = 0 x = -2/8 = -a million/4 so that you obtained 2 roots which fulfill the equation x = 8/9 x = -a million/4
2016-11-25 20:53:16 · answer #4 · answered by ? 4 · 0⤊ 0⤋
just square the both of them
16x^2 + 8x +1 + 9x^2 +49 -42x
25x^2 - 34x + 50
2006-12-11 04:55:18 · answer #5 · answered by tanj 4 · 0⤊ 0⤋
(4x+1)(4x+1)+(3x-7)(3x-7)
= (16x^2+8x+1)+(9x^2-42x+49)
= 25x^2-34x+50
2006-12-11 04:55:38 · answer #6 · answered by Ant C 1 · 0⤊ 0⤋
(4x+1)(4x+1)+(3x-7)(3x-7)
(16x2+8x +1)+(9x2-42x+49)
25x2-34x+50
2006-12-11 04:56:01 · answer #7 · answered by snowgoose8 2 · 0⤊ 0⤋
(a+b)^2=a^2+2ab+b^2
16x^2+8x+1+9x^2-42x+49=25x^2-34x+50 end.
2006-12-11 04:57:05 · answer #8 · answered by grassu a 3 · 0⤊ 0⤋
16x^3+1^3+9x^3-49
25x^3-50
I don't know, that's as far as i can get...............
2006-12-11 04:55:40 · answer #9 · answered by Anonymous · 0⤊ 0⤋