What is 3 times the anti derivative of (x^4-5x^2+x)dx?

Question

Calculus Integrals

Answer 1

here so you can stop asking other people how to do antidirivatives: to get the antiderivative, you add one to the exponent of the expression and then devide the expression by the exponent

eg. X^4, add 1 to 4 changing the exponent to 5 and then devide x^5 by 5 leaving you with 1/5X^5

in a polynomial such as the one you have there, you can basically look at each addition or subtraction sign as a seperator. that means you just have to take the antidirivite of x^4 then subtract the antidirivative of 5X^2 then add the antiderivative of X. then multiply the final thing by 3 and your done

3(1/5X^5 - 5/3X^3 + 1/2X^2)

Answer 2

23*

Answer 3

-37