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2006-12-11 02:43:37 · 6 answers · asked by amit p 1 in Computers & Internet Hardware Laptops & Notebooks

6 answers

To use RAM efficiently on a PC it must all run at the same speed. If indeed this were "really" possible it would slow down the performance of the RAM on your mainboard.

So Vista "may" see it as RAM .... unless the BIOS sees it as such it's just a "virtual" configuration or similation of true RAM so far as the OS is concerned. You may as well just increase your "swap file" size & get the same results.

Last thing .... CPU access to the pen drive is via the "data bus" as opposed to RAM accessed via the "memory bus".... this fact alone should be enough to dismiss any illusions about using such devices as true RAM.

regards,
Philip T

2006-12-11 03:00:16 · answer #1 · answered by Philip T 7 · 0 0

No for now. They are two different types of RAMS. The RAM in your computer is volatile RAM but the one in pen drive is flash memory. I heard that Windows Vista has a trick on virtualizing the flash memory, treating it as volatile but I'm not sure.

2006-12-11 12:47:29 · answer #2 · answered by jlryan87 2 · 0 1

No. The two forms of memory are not compatible. The memory in your computer (RAM) is known as volatile memory. When ydur comp is shut off, anything that was in that memory dies. The memory in your flash drive is known as "flash memory" and retains everything in it's memory without the need for a power source. The way that the computer writes to the two is completely different plus, the memory in your flash drive is much much slower than that inside of your computer. Adding that as RAM would only bog down your system.

2006-12-11 10:51:03 · answer #3 · answered by Chris S 5 · 0 2

yes , here is the tutorial to use pen drive as RAM ......http://goo.gl/4TNOIw

2014-08-21 01:44:15 · answer #4 · answered by Anonymous · 0 0

Windows Vista has the capability to do this, but other than that, no.

2006-12-11 10:48:23 · answer #5 · answered by Yoi_55 7 · 0 0

if it could be accomplished, you wouldn't be asking this question.

2006-12-11 10:48:30 · answer #6 · answered by RJ 2 · 0 1

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