I'm over at my parents house right now hogging the computer lol.
2006-12-11 01:47:26 · 14 answers · asked by munesliver 6 in Entertainment & Music ➔ Polls & Surveys
I'd go to any length. lol.
2006-12-11 01:49:50 · answer #1 · answered by Joni J 6 · 1⤊ 0⤋
Well the last couple of weeks, I've been sitting in a hall way, on the floor, because we couldn't get the laptop to work wireless. I'm back upstairs in comfort now though because McCatterie is a smart cookie!
Glad to see you about the site, hope all is going well!...
2006-12-11 11:18:46 · answer #2 · answered by Anonymous · 2⤊ 0⤋
My computer is not working, so sometimes I go to my uncles during the weekends to get onto Yahoo. Right now I am at work on Yahoo. Yeah, I think I am addicted! LOL
2006-12-11 09:50:51 · answer #3 · answered by Anonymous · 1⤊ 0⤋
I have sneaked on the computer at work in the past, but now I won't. Sometimes I miss a night here and there. Real life takes precedence.
2006-12-11 09:51:41 · answer #4 · answered by Anonymous · 2⤊ 0⤋
An y lengths
2006-12-11 09:51:37 · answer #5 · answered by don;t know 3 · 1⤊ 0⤋
I would climb the highest mountains to get a clear signal for my laptop just to get to Y/A!
I would crawl to Best Buy if it meant getting a new PC, just to get my Y/A fix...
I would even grease up Oprah with olive oil & lick it off if it meant quick & continued access to Y/A!!!
2006-12-11 09:56:06 · answer #6 · answered by Anonymous · 2⤊ 0⤋
I have to admit...since becoming employed again,
YA has become not so addictive...although, there
are a few favorite askers that I check every day or two
2006-12-11 20:38:15 · answer #7 · answered by persnickety1022 7 · 0⤊ 0⤋
I can survive a day w/o it.
Maybe 2. but not more than 3...
:) LoL...
2006-12-11 09:53:27 · answer #8 · answered by Anonymous · 0⤊ 0⤋
I wouldn't. This is something I do to kill time and gain/ give wisdom at the same time.
2006-12-12 21:39:50 · answer #9 · answered by Crossroads Keeper 5 · 0⤊ 0⤋
I'd go all the way to where you are!
2006-12-11 09:50:56 · answer #10 · answered by Bianca 3 · 1⤊ 0⤋