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why is a jeepney of mass 2000kg more difficult to stop than a tricycle of mass 1000 kg when both are traveling at the same initial speed. its a practical question, but answer it scientifically (physics) :)

2006-12-10 21:57:12 · 4 answers · asked by Misa 1 in Science & Mathematics Physics

4 answers

the jeepney is twice as heavy as the tricycle, why wouldnt it be twice as hard to stop?
and by the way, wtf is a jeepney? and who is on this tricycle, an elephant?

2006-12-10 22:00:18 · answer #1 · answered by Anonymous · 0 0

Actually it is depends on Momentum of the Body.

Momentum = Mass * Acceleration

Lets consider acceleration of both jeepney & tricycle is 'a'.
Then
Momentum of jeepney = 2000(kg) * a;
and
Momentum of tricycle = 1000(kg) * a;

From above two equations,
whose momentum will high will hard to stop.

Now got your answer.

2006-12-10 22:13:14 · answer #2 · answered by durgesh 1 · 0 0

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2016-09-03 08:31:43 · answer #3 · answered by ? 4 · 0 0

There is a law, called Newton's Second law of motion, which states that the rate of change of momentum is directly proportional to impressed force. Now momentum means the mass X velocity. To stop a moving object, you have to reduce its momentum to zero.
Let initial velocity is u and final velocity is v (=0) So initial momentum is mu and final momentum is mv. So change of momentum is (mv-mu). Therefore rate of change of momentum is (mv-mu)/t (t is time)
now, to stop we apply a force, say, P
so P is proportional to (mv-mu)/t. Since final velocity is zero, so mv = 0. So P is proportional to -mu/t
In your example, the velocities of jeepny and tricycle are same, only their m values are different. So to stop a heavier body, we have to apply greater amount of force.

2006-12-10 22:29:40 · answer #4 · answered by saudipta c 5 · 0 0

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