2 batsman are on 94. 2 balls remaining and 7 runs to win and both the batsman made their century adn won the match. Answer me how?
2006-12-10 20:45:06 · 7 answers · asked by balaji 1 in Sports ➔ Cricket
First Batsmen plays a short take one run and during overthrow ball hit the helmet of wicket keeper giving five more runs to the first batsman than second one hit the ball for a six.
2006-12-10 21:30:30 · answer #1 · answered by Idrees 2 · 0⤊ 0⤋
First ball: Wide ball, 1st batsmen hits a six. His hundred completed.
2nd ball: 1 run taken
3rd: The 2nd batsman hits a sixer too. He gets his century!!!
2006-12-11 05:16:19 · answer #2 · answered by (^_^) 5 · 0⤊ 0⤋
First ball: Batsman hit and run 3 runs and there is overthrow and ball crosses boundry for four runs. The umpire signals one short. Total runs - six and hence one batsman completes century and one ball to go and one run for win and the other batsman on strike.
Last ball: the other batsman on strike hits it for six and completes his century also.
2006-12-11 05:09:34 · answer #3 · answered by shrimal_sandeep 3 · 0⤊ 1⤋
in first ball ,the batsmen hits the ball by reverse sweep & it hits the helmet(so 5 runs + 1 runs) completed his century......now its other batsmen turn......1 run remaining in 1 ball..the only way to score century & win the match is to hit six......
2006-12-11 06:13:42 · answer #4 · answered by Anonymous · 0⤊ 0⤋
1st ball. Sweeps it really fine hits helmet and a single ( 5 +1 )
2nd ball: The other batsmen hits a six.
2006-12-11 08:08:38 · answer #5 · answered by Hmmmmm 3 · 0⤊ 0⤋
learn more about no balls and wide balls.
then u can find the solution..
2006-12-11 05:24:57 · answer #6 · answered by tdapower 3 · 0⤊ 0⤋
critical question....i will wait for all the other answers....
2006-12-11 04:59:12 · answer #7 · answered by Anonymous · 0⤊ 0⤋