A metal M forms an oxide M2O3, that contains 68.4% of the metal by mass. calculate the molar mass of the metal.
A) 51.9 g/mol
B) 68.4 g/mol
C) 106 g/mol
D) 23.9 g/mol
E) 45.6 g/mol
PLEASE EXPLAIN
2006-12-10 20:17:58 · 3 answers · asked by Whatever 1 in Science & Mathematics ➔ Chemistry
we know that the molar mass of O is 16.
the compound molar mass will be (16x3)+(2M) = 48+2M
2M : (2M+48) = 68.4 : 100
M : (M+24) = 34.2 : 50
34.2M + 820.8 = 50M
820.8 = 15.8 M
M = 51.9 g/mol
2006-12-10 20:26:32 · answer #1 · answered by Papilio paris 5 · 0⤊ 0⤋
If 68.4% of the compound is M then there are two M for every 3 O
O is molar mass of 16, so 100-68.4=31.6% of it is from three O = 48.
So the molar mass of the metal is equal to 34.2% and each percentage point is equal to 48/31.6 = 1.52
A) 51.9 g/mol = 34.2 * 1.52
2006-12-11 04:23:26 · answer #2 · answered by feanor 7 · 0⤊ 0⤋
whats the formula?
2006-12-11 04:19:37 · answer #3 · answered by Anonymous · 0⤊ 2⤋