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I am looking for any relationship that talks about relation between static charge i.e ESD in a room and the particle count. I am told that high particle count can lead to high static charge activity in the area. If yes, is there a method for determining the same. Please help

2006-12-10 19:03:09 · 4 answers · asked by nivanp 2 in Science & Mathematics Physics

4 answers

I spent 2 years of my life determining the effect of negative air ions on asthma. During my study, I conducted a survey of particle counts in the bedrooms of a number of patients. Some of which had active ionizers in their bedroom and some had inactive ones.

Ionizers basically expel a raft of ions into the atmosphere, much the same as static electricity. These ions tend to attach themselves to particles, whereupon they are attracted to any "grounded" or "earthed" material.

Without an ionizer in a room, static electricity is generated through the separation of dissimilar materials (such as walking on nylon carpet in rubber soled shoes). The static electricity in itself will not create particles, but anything carrying static will attract these particles.

So, I would suggest that the reverse of what you are saying is true. If there is a large amount of static in a room (be it from an ionizer or other static source), particles will be attracted to the static carrying body or any grounded surface so they become obvious to the casual observer. If you put an ionizer against the wall, a "dark shadow" of dust particles will appear on the wall within a few days. It has not created the dust, but it has simply concentrated it inot one area of the wall.

Hope this helps.

2006-12-10 20:46:27 · answer #1 · answered by Mez 6 · 0 1

Yes There is relationship between particle count and static charge . The same principle is applied in Geiger Miller counter.

2006-12-12 14:20:29 · answer #2 · answered by abhi s 1 · 0 0

a million. Convex lens types photos that are .Magnified, faded or of d comparable length. Its photos are genuine different than while d obj is placed btw the Pole and significant concentration, the image is then digital. Its used to correction HYPERMETROPIA ie long sightedness Concave lens, its image are vittual, faded and btw Pole and significant concentration. Its used to ultimate MYOPIA ie Shortsightedness. 2.a u=20cm, v=?, f=8cm. a million/f = a million/u + a million/v a million/8 = a million/20 +a million/v 8 = 20v/v + 20 8v + a hundred and sixty = 20v 12v = a hundred and sixty v = a hundred and sixty/12 =13.33cm b. 3/20 = v/13.33 v = (3x13.33)/20 v = 2cm Hook u up wit extra later

2016-12-11 06:44:42 · answer #3 · answered by sickels 4 · 0 0

yes

2006-12-10 20:02:56 · answer #4 · answered by With Eyes That See 2 · 0 0

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