English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

The density of water is 1.0 g/mL, whereas that of mercury is 13.6 g/mL.

What is the pressure in atmospheres on the body of a diver if he is 40. ft below the surface of the water when atmospheric pressure at the surface is 0.98 atm?

2006-12-10 18:09:23 · 2 answers · asked by magicalplaygirl 1 in Science & Mathematics Chemistry

2 answers

(I answer your title 760mm Hg = 760*13.6 =10336 mm water =10.3m)
ro is for water 10^3 kg/m^3 for mercury 13.6 10^3 kg/m^3


YOUR PROBLEM

40 feet correspond to 0.3048*0 =12.192m

The pressure of a column of fluid is in Pascal

h ro g ; h in meters ro in kg/m^3 , g=9.81m/s^-2

here 12.192*1000*9.81 =119604 Pa =1.192atm

So, the pressure on the diver is 1.192+0.98 = 2.17 atm


Excuse me. I am from a country were with such problems we give the units.
I found in a converter 1 Atm = 100000 pa, If you use an other value (not very different, correct)

2006-12-10 18:50:08 · answer #1 · answered by maussy 7 · 0 0

Water barometers are about 10 meters high.
So I suggest multiplying 760 by 13.6, and converting to meters!

2006-12-10 18:43:34 · answer #2 · answered by Gervald F 7 · 0 0

fedest.com, questions and answers