Find the length of each side of the rectangle so that it has the given perimeter.?

Question

The box has 2x -5 on the top and the x is given on the side.

P = 50 inchs

2x - 5
--------------------
- -
- - x
- -
--------------------
Thats the best visual I can do for a box to help you answer my question.

Answer 1

10 and 15

The perimeter is 50, so that means 2x-5 + x equals 2 sides out of 4.

If the perimeter is 50, then 2 sides equals 25, therefore:
2x-5 + x = 25
3x = 30
x = 10
and
2x - 5 = 15

So 2 sides of 10 and 2 sides of 15.


Okay Spurs, for a few minutes there, you had "a" as an answer. What's the deal? Had to reserve your spot for the first answer and then take 5 minutes to do the math?

Answer 2

The perimeter is just the length of all the sides added together. In this case, the vertical sides are x and the horizontal sides are 2x-5. So the perimeter is 2(x)+2(2x-5)=6x-10.

Set 6x-10 equal to 50 and solve.

x is 10 inches.

Answer 3

Since perimeter = 2 x length + 2 x width, you should be able to substitute directly:
50 = 2( 2x-5) + 2x or 6x-10. Then 60=6x and x=10 and 2x-5=15.

Answer 4

P = 2(2x-5) +2(x)
50=4x -10 + 2x
60=6x

x=10 inches

Answer 5

x=10 in; 2x-5 = 15in

P = 50in

50= 2(2x-5)+2x

50= 4x-10+2x

60 =6x

x=10

2x-5 =15

Answer 6

Here it is:
2(2x-5)+(2x)= 50
4x-10 + 2x= 50
6x-10= 50
6x=60
x=10

any questions?

Answer 7

write the equation- 2(2x-5)+2x=50
4x-10=2x=50
6x-10=50
6x=60
x=10
your sides are 10,10,15,15

Answer 8

perimeter = 2 x + 2y

50=2x+2(2x-5)
50=2x+4x-10
50+10=4x+2x
60=6x
x=10 one side

other side is y (other side)=2x-5
y=2(10)-5
y=15 other side

Answer 9

Uhh isnt each side like 10? I have no idea..I think im wrong!
I did 7.5 x 2-5 = 10.

Its 10~10~15~15!!!

Answer 10

2(2x-5)+2x=50
4x-10+2x=50
6x=60
x=10
length=2x-5=15
breadth=x=10