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Na2O + H2O --> 2*NaOH
eq. wt.: 62 : 18 : 80

The conversion factor is (80/62) = 1.29

I have the answer (1.50%).

I don't know how to get the answer. I am not sure the answer is right or wrong. Please help me.


Thank you very much.

2006-12-10 17:05:10 · 1 answers · asked by No Name 1 in Science & Mathematics Chemistry

Table:

Investigated Normality 1.0N ---- 0.75N ------------ 0.50N

Corresponding Na2Oeq. 1.50% ------1.15%---------0.81%

How can you find out the Na2Oeq content to the corresponding normality solution?

Thank you very much in advanced.

2006-12-10 19:41:32 · update #1

1 answers

Your answer seems me wrong

with the conversion factor you see that 6
62g of Na2O correspond to 80 g of NaOH so
the ration Na2O/NaOH is 62/80 = 0.775

0.775 for 1g corresponds to 77.5g for 100g

so the % is 77.5%

2006-12-10 17:43:26 · answer #1 · answered by maussy 7 · 0 0

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